Assume that a researcher randomly selects 14 newborn babies and counts the number of girls selected, x. The probabilities
corresponding to the 14 possible values of x are summarized in the given table. Answer the question using the table. $$\begin{array}{l}
\text { Probabilities of Girls }\
\begin{array} { | c | c | c | c | c | c | }
\hline x \text { (girls) } & P ( x ) & x \text { (girls) } & P ( x ) & x \text { (girls) } & P ( x ) \
\hline 0 & 0.000 & 5 & 0.122 & 10 & 0.061 \
1 & 0.001 & 6 & 0.183 & 11 & 0.022 \
2 & 0.006 & 7 & 0.210 & 12 & 0.006 \
3 & 0.022 & 8 & 0.183 & 13 & 0.001 \
4 & 0.061 & 9 & 0.122 & 14 & 0.000 \
\hline
\end{array}
\end{array}$$
-Find the probability of selecting 9 or more girls.
A) 0.001
B) 0.212
C) 0.061
D) 0.122

Question

Assume that a researcher randomly selects 14 newborn babies and counts the number of girls selected, x. The probabilities
corresponding to the 14 possible values of x are summarized in the given table. Answer the question using the table. $$\begin{array}{l}
\text { Probabilities of Girls }\
\begin{array} { | c | c | c | c | c | c | } 
\hline x \text { (girls) } & P ( x ) & x \text { (girls) } & P ( x ) & x \text { (girls) } & P ( x ) \
\hline 0 & 0.000 & 5 & 0.122 & 10 & 0.061 \
1 & 0.001 & 6 & 0.183 & 11 & 0.022 \
2 & 0.006 & 7 & 0.210 & 12 & 0.006 \
3 & 0.022 & 8 & 0.183 & 13 & 0.001 \
4 & 0.061 & 9 & 0.122 & 14 & 0.000 \
\hline
\end{array}
\end{array}$$
-Find the probability of selecting 9 or more girls.
A) 0.001
B) 0.212
C) 0.061
D) 0.122

Quizplus · Accepted Answer

To find the probability of selecting 9 or more girls, we need to add up the probabilities for x = 9, 10, 11, 12, 13, and 14.

P(x = 9 or more) = P(x = 9) + P(x = 10) + P(x = 11) + P(x = 12) + P(x = 13) + P(x = 14)

= 0.122 + 0.061 + 0.022 + 0.006 + 0.001 + 0.000

= 0.212

Therefore, the best choice is B.

Assume That a Researcher Randomly Selects 14 Newborn Babies and Counts