Find the variance for the given data. Round your answer to one more decimal place than the original data. To get the best deal on a microwave oven, Jeremy called six appliance stores and asked the cost of a specific model. The prices he
Was quoted are listed below: $\begin{array} { l l l l l l } \$ 663 & \$ 273 & \$ 410 & \$ 622 & \$ 174 & \$ 374 \end{array}$

Question

Find the variance for the given data. Round your answer to one more decimal place than the original data. To get the best deal on a microwave oven, Jeremy called six appliance stores and asked the cost of a specific model. The prices he
Was quoted are listed below:

\begin{array} { l l l l l l } \$ 663 & \$ 273 & \$ 410 & \$ 622 & \$ 174 & \$ 374 \end{array}

Quizplus · Accepted Answer

The formula for variance is:

$V=\dfrac{\sum(x-\bar{x})^2}{n-1}$

where $x$ is each data point, $\bar{x}$ is the mean, and $n$ is the number of data points.

To find the variance for the given data, we first need to find the mean:

$\bar{x}=\dfrac{\sum x}{n}=\dfrac{663+273+410+622+174+374}{6}=427$

Next, we can calculate the sum of squared deviations from the mean:

$\sum(x-\bar{x})^2=(663-427)^2+(273-427)^2+(410-427)^2+(622-427)^2+(174-427)^2+(374-427)^2=151652$

Finally, we can plug these values into the formula for variance:

$V=\dfrac{\sum(x-\bar{x})^2}{n-1}=\dfrac{151652}{6-1}=36,838.3$ (rounded to one more decimal place than the original data)

Therefore, the best choice is C, with a variance of $36,838.3$ dollars squared.

Find the Variance for the Given Data $663$273$410$622$174$374\begin{array} { l l l l l l } \$ 663 & \$ 273 & \$ 410 & \$ 622 & \$ 174 & \$ 374 \end{array}$663​$273​$410​$622​$174​$374​

Find the Variance for the Given Data $\begin{array} { l l l l l l } \$ 663 & \$ 273 & \$ 410 & \$ 622 & \$ 174 & \$ 374 \end{array}$