Find the z-score corresponding to the given value and use the z-score to determine whether the value is unusual.
Consider a score to be unusual if its z-score is less than -2.00 or greater than 2.00. Round the z-score to the nearest tenth
if necessary.
-A body temperature of 96.7° F given that human body temperatures have a mean of 98.20° F and a standard deviation of 0.62°.
A) -1.5; not usual
B) 2.4; unusual
C) -2.4; not unusual
D) -2.4; unusual

Question

Quizplus · Accepted Answer

The z-score can be calculated using the formula:

z = (x - μ) / σ

where x is the given value (body temperature of 96.7°F), μ is the mean (98.20°F), and σ is the standard deviation (0.62°F).

z = (96.7 - 98.20) / 0.62 = -2.42 (rounded to the nearest tenth)

Since the z-score is less than -2.00, the body temperature of 96.7°F is considered unusual. Therefore, the answer is D.

Find the Z-Score Corresponding to the Given Value and Use