A restaurant that bills its house account monthly is concerned that the average monthly bill exceeds
$200 per account. A random sample of twelve accounts is selected, resulting in a sample mean of
$220 and a standard deviation of $12. The t-test is to be conducted at the 5% level of significance.
Given the following printout, what can you determine?
A) The alternate hypothesis is μ ≤ 200
B) You should accept the null hypothesis at the 0.05 level of significance.
C) There is less than a 1% chance of getting these results if the null hypothesis is true, so you have very strong evidence to suggest that the average bill is more than $200.
D) There is less than a 1% chance of getting these results if the null hypothesis is true, so you have very strong evidence to suggest that the average bill is less than $200.
E) The alternate hypothesis is μ ≤ 200 and you should accept the null hypothesis at the 0.05 level of significance.
Correct Answer:
Verified
Q128: Based on the Nielsen ratings, the local
Q129: For a null hypothesis, H0: µ =
Q130: The average cost of tuition, room and
Q131: The Jamestown Steel Company manufactures and assembles
Q132: The printout below refers to the weekly
Q134: The Jamestown Steel Company manufactures and assembles
Q135: The Jamestown Steel Company manufactures and assembles
Q136: Using a 5% level of significance and
Q137: The printout below refers to the weekly
Q138: The printout below refers to the weekly
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents