Using the bond energies provided below, calculate ΔH° for the reaction CH₄(g) + 4Cl₂(g) → CCl₄(g) + 4HCl(g)
Bond energies: C-H = 413 kJ/mol, Cl-Cl = 243 kJ/mol, C-Cl = 339 kJ/mol, H-Cl = 427 kJ/mol

Question

Quizplus · Accepted Answer

The ΔH° is calculated using bond energies: ΔH° = Σ(Bond energies of reactants) - Σ(Bond energies of products). For reactants: 4(C-H) + 4(Cl-Cl) = 4(413) + 4(243) = 2624 kJ. For products: 4(C-Cl) + 4(H-Cl) = 4(339) + 4(427) = 3064 kJ. ΔH° = 2624 - 3064 = -440 kJ.

Using the Bond Energies Provided Below, Calculate ΔH° for the Reaction