Calculate q when 28.6 g of water is heated from 22.0°C to 78.3°C.

Name: Calculate q when 28.6 g of water is heated from 22.0°C to 78.3°C.
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Question

Quizplus · Accepted Answer

q = mCΔT
Here, m = 28.6 g is the mass of water, C = 4.184 J/g°C is the specific heat capacity of water, ΔT = (78.3°C - 22.0°C) = 56.3°C is the change in temperature.
Substituting these values gives:
q = (28.6 g)(4.184 J/g°C)(56.3°C) = 6.74 kJ
Therefore, the correct answer is choice C, which is 6.74 kJ.

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