Ethylene glycol, used as a coolant in automotive engines, has a specific heat capacity of 2.42 J/(g·K). Calculate q when 3.65 kg of ethylene glycol is cooled from 132°C to 85°C.

Question

Quizplus · Accepted Answer

To calculate the heat (q) absorbed or released, we use the formula q = mcΔT, where m is the mass in grams, c is the specific heat capacity, and ΔT is the change in temperature. Here, m = 3.65 kg = 3650 g (since 1 kg = 1000 g), c = 2.42 J/(g·K), and ΔT = 85°C - 132°C = -47°C. Plugging these values in, we get q = 3650 g * 2.42 J/(g·K) * (-47 K) = -420,390 J = -420 kJ (since 1 kJ = 1000 J).

Ethylene Glycol, Used as a Coolant in Automotive Engines, Has