What is the final temperature when 20.0 g of water at 25°C is mixed with 30.0 g of water at 80°C?

Question

Quizplus · Accepted Answer

To solve this problem, we can use the formula:
(m1 x c1 x ΔT1) + (m2 x c2 x ΔT2) = 0
where m is mass, c is specific heat capacity, ΔT is the change in temperature.

Plugging in the values:
(20.0 g) x (1 cal/g°C) x (Tf - 25°C) + (30.0 g) x (1 cal/g°C) x (Tf - 80°C) = 0

Simplifying and solving for Tf:
20(Tf - 25) + 30(Tf - 80) = 0
20Tf -500 + 30Tf - 2400 = 0
50Tf - 2900 = 0
50Tf = 2900
Tf = 58°C

Therefore, the final temperature is 58°C, which corresponds to choice D.

What Is the Final Temperature When 20