Calcium hydroxide, which reacts with carbon dioxide to form calcium carbonate, was used by the ancient Romans as mortar in stone structures. The reaction for this process is Ca(OH) ₂(s) + CO₂(g) → CaCO₃(s) + H₂O(g) ΔH = −69.1 kJ
What is the enthalpy change if 3.8 mol of calcium carbonate is formed?

Question

Quizplus · Accepted Answer

The enthalpy change for the reaction as given is −69.1 kJ per mole of calcium carbonate formed. For 3.8 moles, the total enthalpy change would be 3.8 moles × −69.1 kJ/mole = −262.58 kJ, which is closest to −260 kJ.

Calcium Hydroxide, Which Reacts with Carbon Dioxide to Form Calcium