The compound carbon suboxide, C₃O₂, is a gas at room temperature. Use the data supplied to calculate the heat of formation of carbon suboxide. (Data: 2CO(g) + C(s) → C₃O₂(g) ΔH° = 127.3 kJ/mol
And: ΔH_f° of CO(g) = −110.5 kJ/mol)

Question

Quizplus · Accepted Answer

The heat of formation ($\Delta H_f^\circ$) of carbon suboxide can be calculated using the given reaction and data. The reaction is: $2CO(g) + C(s) \rightarrow C_3O_2(g)$ with $\Delta H^\circ = 127.3 \,kJ/mol$. The heat of formation of CO(g) is $-110.5 \,kJ/mol$. Since there are 2 moles of CO, the total heat of formation for CO is $2 \times -110.5 \,kJ/mol = -221 \,kJ/mol$. The heat of formation of carbon suboxide is the sum of the heat of the reaction and the total heat of formation of the reactants: $127.3 \,kJ/mol - 221 \,kJ/mol = -93.7 \,kJ/mol$.

The Compound Carbon Suboxide, C3O2, Is a Gas at Room

The Compound Carbon Suboxide, C₃O₂, Is a Gas at Room