A compressed gas cylinder containing 1.50 mol methane has a volume of 3.30 L. What pressure does the methane exert on the walls of the cylinder if its temperature is 25°C? A)9.00 × 10 ⁻² atm B)0.933 atm C)1.11 atm D)1.70 atm E)11.1 atm

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To find the pressure exerted by the methane gas, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/(K·mol)), and T is the temperature in Kelvin. First, convert the temperature to Kelvin: T = 25°C + 273.15 = 298.15 K. Then, plug in the values: P = (nRT)/V = (1.50 mol * 0.0821 L·atm/(K·mol) * 298.15 K) / 3.30 L = 11.1 atm.

A Compressed Gas Cylinder Containing 1