Aluminum oxide, Al₂O₃, is used as a filler for paints and varnishes as well as in the manufacture of electrical insulators. Calculate the number of moles in 47.51 g of Al₂O₃. A)2.377 mol B)2.146 mol C)1.105 mol D)0.4660 mol E)0.4207 mol

Question

Quizplus · Accepted Answer

To calculate the number of moles in 47.51 g of aluminum oxide (Al2O3), first find the molar mass of Al2O3. The molar mass of Al (Aluminum) is approximately 26.98 g/mol, and the molar mass of O (Oxygen) is approximately 16.00 g/mol. Therefore, the molar mass of Al2O3 = (2 * 26.98) + (3 * 16.00) = 53.96 + 48.00 = 101.96 g/mol. Then, the number of moles of Al2O3 in 47.51 g can be calculated using the formula: moles = mass (g) / molar mass (g/mol), which gives moles = 47.51 g / 101.96 g/mol = 0.4660 mol.

Aluminum Oxide, Al2O3, Is Used as a Filler for Paints

Aluminum Oxide, Al₂O₃, Is Used as a Filler for Paints