The redox reaction of peroxydisulfate with iodide has been used for many years as part of the iodine clock reaction which introduces students to kinetics. If E°_cell = 1.587 V and E° of the cathode half-cell is 0.536 V, what is E° of the anode half-cell? S₂O₈²⁻(aq) + 2H⁺ + 2I⁻(aq) → 2HSO₄⁻(aq) + I₂(aq)

Question

Quizplus · Accepted Answer

Using the standard reduction potentials given for the cathode and overall reaction, we can solve for the standard reduction potential of the anode half-cell using the equation:
E°cell = E°cathode - E°anode

Substituting the given values:
1.587 V = 0.536 V - E°anode

Solving for E°anode:
E°anode = -1.051 V

Therefore, the best choice is A) -1.051 V.

The Redox Reaction of Peroxydisulfate with Iodide Has Been Used