Examine the following half-reactions and select the strongest oxidizing agent among the substances. [PtCl4]2−(aq) + 2e− ⇄ Pt(s) + 4Cl−(aq) E° = 0.755 V
RuO4(s) + 8H+(aq) + 8e− ⇄ Ru(s) + 4H2O(l) E° = 1.038 V
FeO42−(aq) + 8H+(aq) + 3e− ⇄ Fe3+(aq) + 4H2O(l) E° = 2.07 V
H4XeO6(aq) + 2H+(aq) + 2e− ⇄ XeO3(aq) + 3H2O(l) E° = 2.42 V
A) [PtCl 4] 2-( aq)
B) RuO 4( s)
C) HFeO 4− ( aq)
D) H 4X eO 6( aq)
E) Cl −( aq)
Correct Answer:
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