A voltaic cell consists of a Mn/Mn²⁺ electrode (E° = −1.18 V) and a Fe/Fe²⁺ electrode (E° = −0.44 V). Calculate [Fe²⁺] if [Mn²⁺] = 0.050 M and E_cell = 0.78 V at 25°C.

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The cell potential (E°cell) is calculated using the standard reduction potentials: E°cell = E°cathode - E°anode = -0.44 V - (-1.18 V) = 0.74 V. The Nernst equation is used to find [Fe²⁺]: Ecell = E°cell - (RT/nF)ln(Q), where Q = [Mn²⁺]/[Fe²⁺]. Solving for [Fe²⁺] with Ecell = 0.78 V gives approximately 1.1 M.

A Voltaic Cell Consists of a Mn/Mn2+ Electrode (E° =

A Voltaic Cell Consists of a Mn/Mn²⁺ Electrode (E° =