Sulfuryl dichloride is formed when sulfur dioxide reacts with chlorine. The data refer to 298 K. SO₂(g) + Cl₂(g) → SO₂Cl₂(g)
What is the value of ΔG° for this reaction at 600 K?

Question

Sulfuryl dichloride is formed when sulfur dioxide reacts with chlorine. The data refer to 298 K. SO₂(g) + Cl₂(g) → SO₂Cl₂(g) What is the value of ΔG° for this reaction at 600 K?

Quizplus · Accepted Answer

We can use the formula ΔG°(600 K) = ΔH°(600 K) - TΔS°(600 K), where ΔH° and ΔS° are the enthalpy and entropy changes at 298 K, and we assume that they do not change significantly with temperature. We can find ΔH° and ΔS° from standard enthalpies of formation and standard entropies:

ΔH° = (-395.7 kJ/mol + 121.7 kJ/mol) - (-300.4 kJ/mol) = -174.0 kJ/mol
ΔS° = (256.6 J/mol·K + 223.0 J/mol·K) - (205.2 J/mol·K) = 274.4 J/mol·K

Substituting these values, we get:

ΔG°(600 K) = -174.0 kJ/mol - (600 K)(0.2744 kJ/mol·K) = 28.4 kJ/mol

Therefore, the answer is D, 28.4 kJ.

Sulfuryl Dichloride Is Formed When Sulfur Dioxide Reacts with Chlorine