The solubility of silver chromate is 0.0287 g/1.0 L of solution. What is the K_sp for Ag₂CrO₄?

Question

Quizplus · Accepted Answer

The solubility product constant (Ksp) for Ag2CrO4 can be calculated using the solubility and the dissociation equation: Ag2CrO4 ⇌ 2Ag+ + CrO4^2-. The molar mass of Ag2CrO4 is approximately 331.73 g/mol. The molarity of Ag2CrO4 is 0.0287 g/L ÷ 331.73 g/mol = 8.65 × 10^-5 M. The concentration of Ag+ is 2 × 8.65 × 10^-5 M, and CrO4^2- is 8.65 × 10^-5 M. Ksp = [Ag+]^2[CrO4^2-] = (2 × 8.65 × 10^-5)^2 × 8.65 × 10^-5 = 2.6 × 10^-12.

The Solubility of Silver Chromate Is 0