Calculate the solubility of silver chromate, Ag₂CrO₄, in 0.005 M Na₂CrO₄. K_sp = 2.6 × 10⁻¹² A)1.4 × 10⁻⁴M B)3.4 × 10 ⁻⁵ M C)1.1 × 10 ⁻⁵ M D)1.6 × 10 ⁻⁶ M E)

Question

Calculate the solubility of silver chromate, Ag₂CrO₄, in 0.005 M Na₂CrO₄. K_sp = 2.6 × 10⁻¹² A)1.4 × 10⁻⁴M B)3.4 × 10 ⁻⁵ M C)1.1 × 10 ⁻⁵ M D)1.6 × 10 ⁻⁶ M E)< 1.0 × 10 ⁻⁶ M

Quizplus · Accepted Answer

The solubility of Ag₂CrO₄ in a solution containing a common ion (CrO₄²⁻) is calculated using the Ksp expression: Ksp = [Ag⁺]²[CrO₄²⁻]. With [CrO₄²⁻] = 0.005 M from Na₂CrO₄, solve for [Ag⁺]: 2.6 × 10⁻¹² = [Ag⁺]²(0.005), giving [Ag⁺] = 1.1 × 10⁻⁵ M.

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