Consider the reactions of cadmium with the thiosulfate anion. Cd2+(aq) + S2O32−(aq) ⇄ Cd(S2O3) (aq) K1 = 8.3 × 103
Cd(S2O3) (aq) + S2O32−(aq) ⇄ Cd(S2O3) 22−(aq) K2 = 2.5 × 102
What is the value for the equilibrium constant for the following reaction?
Cd2+(aq) + 2S2O32−(aq) ⇄ Cd(S2O3) 22−(aq)
A) 0.030
B) 33
C) 8.1 × 10 3
D) 8.6 × 10 3
E) 2.1 × 10 6
Correct Answer:
Verified
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