The equilibrium constant K_c for the reaction A(g) + B(g) ⇄ C(g)
Is 0.76 at 150°C. If 0.800 mol of A is added to 0.600 mol of B in a 1.00-L container at 150°C, what will be the equilibrium concentration of C?

Question

Quizplus · Accepted Answer

To find the equilibrium concentration of C, set up the expression for Kc: Kc = [C]/([A][B]). Let x be the change in concentration at equilibrium. Then, [C] = x, [A] = 0.800 - x, [B] = 0.600 - x. Substitute these into the Kc expression: 0.76 = x/((0.800-x)(0.600-x)). Solving for x gives x = 0.19 M, which is the equilibrium concentration of C.

The Equilibrium Constant Kc for the Reaction A(g) + B(g)

The Equilibrium Constant K_c for the Reaction A(g) + B(g)