What is the de Broglie wavelength of a neutron with kinetic energy 44.0 keV? The mass of a neutron is 939.6 MeV/c². A) 56.4 pm B) 0.136 pm C) 0.166 pm D) 2.83 pm E) 5.11 pm

Question

Quizplus · Accepted Answer

The de Broglie wavelength of a particle can be calculated using the equation λ = h/p, where h is Planck's constant and p is the momentum of the particle. The momentum of a neutron can be calculated using the equation p = sqrt(2mK), where m is the mass of the neutron, K is the kinetic energy of the neutron.
 
Solving this equation gives:
p = sqrt(2mK) = sqrt(2(939.6 MeV/c^2)(44.0 keV)/(c^2)) = 1.964x10^-22 kg m/s

Using the equation λ = h/p, and h = 6.626x10^-34 J s, we get:
λ = h/p = (6.626x10^-34 J s)/(1.964x10^-22 kg m/s) = 0.136 pm

Therefore, the correct answer is B.

What Is the De Broglie Wavelength of a Neutron with Kinetic