An x-ray photon of energy 3.20 × 10^-15 J has what wavelength? A) 200 nm B) 62.1 pm C) 32.7 nm D) 5.73 pm E) 1.07 nm

Question

Quizplus · Accepted Answer

We can use the equation E=hc/lambda, where E is the energy of the photon, h is Planck's constant, c is the speed of light, and lambda is the wavelength of the photon. Rearranging this equation, we get lambda = hc/E. Plugging in the given values, we get lambda = (6.626 x 10^-34 J s) x (3.00 x 10^8 m/s) / (3.20 x 10^-15 J) = 6.21 x 10^-11 m = 62.1 pm (picometers). Therefore, the best choice is B, with a wavelength of 62.1 picometers.

An X-Ray Photon of Energy 3