What is the ionization energy of the hydrogen atom in the n = 2 state?
A) 13.6 eV
B) −13.6 eV
C) 3.40 eV
D) −3.40 eV
E) −1.51 eV

Question

Quizplus · Accepted Answer

The ionization energy of hydrogen in the n=2 state can be calculated using the formula:
IE = -(RH/n^2)
where RH is the Rydberg constant (13.6 eV), and n is the initial energy level. For n=2, the ionization energy is:
IE = -(13.6 eV/2^2)
IE = -3.4 eV (Note the negative sign indicates that energy is released when the electron is removed, i.e. the hydrogen becomes ionized). Therefore, the best choice is C.

What Is the Ionization Energy of the Hydrogen Atom in the N