In a double-slit experiment, the intensity of the light reaching the center of the screen from one slit alone is I0 and intensity of the light reaching the center from the other slit alone is 9I0. When both slits are open, what is the intensity of the light at the minima nearest the center? A) 4I₀ B) 0 C) 8I₀ D) 2I₀

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Quizplus · Accepted Answer

The intensity at the minima in a double-slit experiment is given by $I_{min} = ( \sqrt{I_1} - \sqrt{I_2} )^2$, where $I_1$ and $I_2$ are the intensities from each slit. Here, $I_1 = I_0$ and $I_2 = 9I_0$, so $I_{min} = ( \sqrt{I_0} - \sqrt{9I_0} )^2 = (1I_0^{1/2} - 3I_0^{1/2})^2 = 4I_0$.

In a Double-Slit Experiment, the Intensity of the Light Reaching