At the Earth's surface, the intensity of solar radiation is approximately 1000 W/m². At a latitude of 44.5 degrees north, when the Sun is highest in the sky on the winter solstice, the Sun's rays are incident at an angle of 68.0 degrees from the vertical. What power is incident upon a 1.00 m × 1.50 m window in a vertical, south-facing wall at this time?

Question

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The correct answer is A.The power incident upon the window is given by the following equation:P = I * A * cos(theta)where:P is the power in wattsI is the intensity of solar radiation in W/m^2A is the area of the window in m^2theta is the angle of incidence in degreesPlugging in the given values, we get:P = 1000 W/m^2 * 1.00 m * 1.50 m * cos(68.0 degrees)P = 1390 WTherefore, the power incident upon the window is 1390 W.

At the Earth's Surface, the Intensity of Solar Radiation Is