A series RLC circuit has a resistance of 500 Ω, an inductance of 20.0 mH, and a capacitance of 2.00 μF. The source provides a voltage of v(t) = (170 V) sin (377t). What is the impedance of this circuit?
A) 0.402 kΩ
B) 1.33 kΩ
C) 1.25 kΩ
D) 1.41 kΩ
E) 2.15 kΩ

Question

Quizplus · Accepted Answer

The impedance of a series RLC circuit is given by 
$Z = \sqrt{R^2 + (\omega L - \frac{1}{\omega C})^2}$, where $\omega$ is the angular frequency of the source voltage.
Substituting the given values, we get:
$Z = \sqrt{(500)^2 + (377 	imes 0.020 - \frac{1}{377 	imes 2 	imes 10^{-6}})^2}$
$Z = 1.41$ k$\Omega$ (rounded to two decimal places)
Therefore, the best choice is (D) 1.41 k$\Omega$.

A Series RLC Circuit Has a Resistance of 500 Ω