A long straight wire is carrying a current of 2.4 A in a region where a uniform magnetic field is perpendicular to the wire. If the magnetic field is 0.52 mT, what is the magnitude of the force on 3.0 m of the wire? A) 1.2 × 10⁻³ N B) 3.7 × 10⁻³ N C) 7.2 × 10⁻³ N D) 3.7 N E) 7.2 N

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Quizplus · Accepted Answer

The magnitude of the force on a current-carrying wire in a magnetic field is given by F = BIL, where F is the force, B is the magnetic field strength, I is the current, and L is the length of the wire in the magnetic field. In this case, B = 0.52 mT, I = 2.4 A, and L = 3.0 m, so F = (0.52 mT)(2.4 A)(3.0 m) = 3.7 × 10⁻³ N.

A Long Straight Wire Is Carrying a Current of 2