A long straight wire is carrying a current of 2.4 A in a region with a uniform magnetic field. If the magnetic field is 0.52 mT and makes an angle of 60° with the wire, what is the magnitude of the force on 3.0 m of the wire?

Question

Quizplus · Accepted Answer

We can find the force on the wire using the formula:

$F = IlB\sin	heta$

where I is the current, l is the length of wire, B is the magnetic field strength, and θ is the angle between the wire and the magnetic field.

Substituting the given values, we get:

$F = (2.4~A)(3.0~m)(0.52~mT)\sin(60^\circ)$

$F = (2.4~A)(3.0~m)(0.52	imes10^{-3}~T)\sin(60^\circ)$  [converting mT to T]

$F = 3.2	imes10^{-3}~N$

Therefore, the answer is D: 3.2 × 10^-3 N.

A Long Straight Wire Is Carrying a Current of 2