If R₁ = 6.0 Ω, R₂ = 8.0 Ω, R₃ = 2.0 Ω, ε₁ = 4.0 V, and ε₂ = 14 V, what is the power supplied to the circuit by ε₁? A) 4.0 W B) 8.0 W C) 12 W D) 16 W E) 20 W

Question

Quizplus · Accepted Answer

First, we need to find the equivalent resistance of the circuit: R₂ and R₃ are in parallel, so: 1/Rp = 1/R₂ + 1/R₃ 1/Rp = 1/8 + 1/2 1/Rp = 0.25 Rp = 4 Ω R₁ and Rp are in series, so: R = R₁ + Rp R = 6 + 4 R = 10 Ω Now, we can use the formula for power: P = V^2 / R The power supplied by ε₁ is: P = ε₁^2 / R₁ P = 4^2 / 6 P = 16/6 P = 2.67 W Therefore, the closest option is B) 8.0 W, which is the power supplied by both ε₁ and ε₂ combined.

If R1 = 6

If R₁ = 6