What is the potential at a distance of 0.0529 nm from a proton?

Name: What is the potential at a distance of 0.0529 nm from a proton?
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The potential V at a distance r from a point charge Q (such as a proton) is given by V = kQ/r, where k is Coulomb's constant (8.99 x 10^9 N m²/C²) and Q is the charge of the proton (1.6 x 10^-19 C). At 0.0529 nm (which is the Bohr radius), the potential is approximately 27.2 V.

What Is the Potential at a Distance of 0