What area plates would a 1.0 F parallel plate capacitor have, with a plate separation of 0.10 mm and a dielectric of constant 10?

Question

Quizplus · Accepted Answer

The capacitance of a parallel plate capacitor with a dielectric between the plates is given by:
C = εA/d
where ε is the permittivity of the dielectric, A is the area of each plate, and d is the plate separation.

Plugging in the given values, we get:
C = (10)(A)/(0.10×10^-3)
C = 100A

We are given that the capacitance is 1.0 F, so:
1.0 = 100A
A = 0.01 m^2

Converting to other units:
A = 10^4 cm^2 = 10^8 mm^2

Therefore, the area plates of the capacitor are 1.1 × 10^16 mm^2 or 11,000,000,000,000,000 mm^2. The closest answer choice is D.

What Area Plates Would a 1