A parallel plate capacitor is charged to 12 V and the voltage source is then disconnected. When the air space between the plates is then filled with a dielectric of constant 6.0, what is the resulting voltage between the plates?

Question

Quizplus · Accepted Answer

The voltage across the capacitor decreases by a factor equal to the dielectric constant when a dielectric is introduced. Since the initial voltage is 12 V and the dielectric constant is 6, the new voltage is 12 V / 6 = 2 V.

A Parallel Plate Capacitor Is Charged to 12 V and the Voltage