If the potential difference across the plates of a capacitor is doubled, what happens to the energy stored?

Question

Quizplus · Accepted Answer

The energy stored in a capacitor is given by the formula $E = \frac{1}{2}CV^2$, where $E$ is the energy, $C$ is the capacitance, and $V$ is the potential difference. If the potential difference is doubled, the energy stored becomes $E = \frac{1}{2}C(2V)^2 = 2^2 \times \frac{1}{2}CV^2$, which is four times the original energy, hence it quadruples.

If the Potential Difference Across the Plates of a Capacitor