The electric field between two charged plates is 7.2 kN/C. If the plates are separated by 3.0 mm, what is the potential difference between them?

Question

Quizplus · Accepted Answer

The potential difference (V) between two plates is given by V = E * d, where E is the electric field and d is the separation distance. Here, E = 7.2 kN/C = 7200 N/C and d = 3.0 mm = 0.003 m. Thus, V = 7200 * 0.003 = 21.6 V, which rounds to 22 V.

The Electric Field Between Two Charged Plates Is 7