What is the force on a proton sitting midway between a pair of parallel conducting plates that are at potentials of −17 V and 55 V, respectively? Their separation distance is 1.5 cm.

Question

Quizplus · Accepted Answer

The electric field between the plates is:$$E = \frac{V}{d} = \frac{55 V - (-17 V)}{1.5 cm} = 4833 V/cm$$The force on the proton is:$$F = qE = (1.6 	imes 10^{-19} C)(4833 V/cm) = 7.7 	imes 10^{-16} N$$

What Is the Force on a Proton Sitting Midway Between