Three point charges are positioned as follows: q₁ is at (0.00 m, 0.00 m), q₂ is at (1.20 m, 0.00 m), and q₃ is at (1.20 m, 1.60 m). If q₁ = 1.00 µC, q₂ = 2.00 µC, and q₃ = 3.00 µC, what is the magnitude of the force on q₂? A) 2.45 × 10^-2 N B) 1.25 × 10^-2 N C) 2.11 × 10^-2 N D) 3.36 × 10^-2 N E) 5.08 × 10^-2 N

Question

Quizplus · Accepted Answer

The force on $q_2$ due to $q_1$ and $q_3$ can be calculated using Coulomb's law. The forces are vector quantities and must be added vectorially. The force between $q_1$ and $q_2$ is attractive and acts along the x-axis, while the force between $q_2$ and $q_3$ acts at an angle due to their positions. Calculating these forces and their resultant gives the magnitude of the total force on $q_2$, which matches choice A when the correct calculations are performed.

Three Point Charges Are Positioned as Follows: Q1 Is at (0.00

Three Point Charges Are Positioned as Follows: Q₁ Is at (0.00