A conducting sphere of radius 10.0 cm holds a net charge of 4.4 µC. What is the surface charge density? A) 0.0 B) 3.5 × 10^-5 C/m² C) 1.1 × 10^-5 C/m² D) 2.2 × 10^-4 C/m² E) 5.6 × 10^-3 C/m²

Question

Quizplus · Accepted Answer

The surface charge density ($\sigma$) is calculated by dividing the total charge ($Q$) by the surface area ($A$) of the sphere. The formula for the surface area of a sphere is $4\pi r^2$, where $r$ is the radius. Given $Q = 4.4 \times 10^{-6}$ C and $r = 0.1$ m, the surface charge density is $\sigma = \frac{Q}{4\pi r^2} = \frac{4.4 \times 10^{-6} C}{4\pi (0.1)^2 m^2} = 3.5 \times 10^{-5} C/m^2$.

A Conducting Sphere of Radius 10