If the electric field due to a point charge is 17 N/C at a distance of 1.5 m, what is the electric flux through a 1.5 m-radius imaginary spherical surface centered on the point charge? A) 120 Nm²/C B) 480 Nm²/C C) 150 Nm²/C D) 320 Nm²/C

Question

Quizplus · Accepted Answer

The electric flux through a spherical surface centered on a point charge is given by $\Phi = E \cdot 4\pi r^2$, where $E$ is the electric field strength and $r$ is the radius of the sphere. Substituting $E = 17 \, \text{N/C}$ and $r = 1.5 \, \text{m}$, we get $\Phi = 17 \cdot 4\pi (1.5)^2 = 17 \cdot 4\pi \cdot 2.25 = 17 \cdot 9\pi = 153\pi \, \text{Nm}^2/\text{C}$. This is approximately 480 Nm$^2$/C, making option B the correct answer.

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