Using 0.0200 mol of an ideal monatomic gas, an isochoric process from state A (230 kPa, 1.0 L) to B (98 kPa, 1.0 L) results in what change in internal energy?
A) −200 J
B) +200 J
C) −375 J
D) +375 J

Question

Quizplus · Accepted Answer

The change in internal energy for an ideal monatomic gas is given by ΔU = (3/2)nRΔT. Since the process is isochoric, the volume is constant, and the change in pressure directly relates to the change in temperature. The decrease in pressure indicates a decrease in temperature, leading to a decrease in internal energy. Calculating ΔU using the given pressures and volume results in approximately −200 J.

Using 00200 Mol of an Ideal Monatomic Gas, an Isochoric Process