A refrigerator removes heat from the freezing compartment at the rate of 20 kJ and rejects 24 kJ into the room per cycle. How much work is required in each cycle?

Name: A refrigerator removes heat from the freezing compartment at the rate of 20 kJ and rejects 24 kJ into the room per cycle. How much work is required in each cycle?
Brand: Quizplus
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Question

Quizplus · Accepted Answer

The work required for each cycle is the difference between the heat rejected and the heat removed, which is 24 kJ - 20 kJ = 4 kJ.

A Refrigerator Removes Heat from the Freezing Compartment at the Rate