If the temperature of 2.000 moles of a monatomic ideal gas is increased by 50 °C, then what is the increase in the internal energy of the gas?

Question

Quizplus · Accepted Answer

The internal energy of a monatomic ideal gas is given by:U = (3/2) nRTwhere:U is the internal energyn is the number of molesR is the ideal gas constantT is the temperatureIf the temperature of the gas is increased by 50 °C, then the new temperature is:T' = T + 50 °CThe increase in the internal energy is:ΔU = U' - U = (3/2) nR(T' - T) = (3/2) nR(50 °C) = (3/2) (2.000 moles) (8.314 J/mol·K) (50 °C) = 1,247 JTherefore, the correct answer is A.

If the Temperature of 2