What is the change in internal energy of 2.00 moles of a monatomic ideal gas that cools from 200 °C to −50 °C?

Name: What is the change in internal energy of 2.00 moles of a monatomic ideal gas that cools from 200 °C to −50 °C?
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Quizplus · Accepted Answer

The change in internal energy (ΔU) for a monatomic ideal gas is given by ΔU = (3/2)nRΔT. Here, n = 2.00 moles, R = 8.314 J/(mol·K), and ΔT = (−50 − 200) °C = −250 K. Calculating gives ΔU = (3/2)(2.00)(8.314)(−250) = −6,236 J.

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