The heat of fusion for ice at 0 °C is 333.7 kJ/kg, the specific heat of water 4.186 kJ/kg °C, and the heat of vaporization of water at 100 °C is 2,256 kJ/kg. What is the energy needed to vaporize 100 grams of ice at starting at 0 °C?

Question

Quizplus · Accepted Answer

To vaporize 100g of ice at 0°C, first melt the ice: 100g * 333.7 kJ/kg = 33.37 kJ. Then heat the water from 0°C to 100°C: 100g * 4.186 kJ/kg°C * 100°C = 41.86 kJ. Finally, vaporize the water: 100g * 2,256 kJ/kg = 225.6 kJ. Total energy = 33.37 + 41.86 + 225.6 = 300.83 kJ, approximately 300.8 kJ.

The Heat of Fusion for Ice at 0 °C Is