A 100 gram glass container contains 200 grams of water and 10 grams of ice all at 0 °C. A 200 gram piece of lead at 100 °C is added to the water and ice in the container. What is the final temperature of the system? (specific heat of ice = 2,000 J/kg °C, specific heat of water = 4,186 J/kg °C, heat of fusion of water = 333.7 kJ/kg, specific heat of glass = 837.2 J/kg °C, specific heat of lead = 127.7 J/kg °C)

Question

Quizplus · Accepted Answer

The heat lost by the lead will first go into melting the ice and then raising the temperature of the water, glass, and lead to an equilibrium temperature. However, given the amount of ice and the heat capacity and mass of the materials involved, all the heat from the lead will be used to melt the ice and warm the system up to 0 °C, but not beyond, as melting the ice itself requires a significant amount of energy. Therefore, the final temperature of the system will be 0 °C, as all the heat from the lead will be absorbed before the temperature of the water can rise above 0 °C.

A 100 Gram Glass Container Contains 200 Grams of Water