An ideal gas at a temperature of 39°C, a pressure of 2.00 atmospheres and a volume of 2.10 liters. What is the temperature if the pressure is halved and the volume is tripled?
A) 155°C
B) 175°C
C) 188°C
D) 195°C
E) 204°C

Question

Quizplus · Accepted Answer

Using the combined gas law, (P1V1)/T1 = (P2V2)/T2, we can find the new temperature. Halving the pressure gives us P2 = 1 atm and tripling the volume gives us V2 = 6.30 L. Plugging in the known values, we get (2.00 atm x 2.10 L)/312K = (1.00 atm x 6.30 L)/T2. Solving for T2, we get T2 = 522K, which is equal to 249°C. However, we must convert this to Celsius by subtracting 273.15, giving us a final answer of 249°C - 273.15 = 195°C. Therefore, choice D is the best answer.

An Ideal Gas at a Temperature of 39°C, a Pressure