A vessel contains 2.00 moles of an ideal gas at standard temperature and pressure (0°C and 1 atm). If the temperature of the gas is changed by 1°C, what is the change in the pressure?
A) 371 Pa
B) 323 Pa
C) 301 Pa
D) 298 Pa
E) 273 Pa

Question

Quizplus · Accepted Answer

The change in pressure can be calculated using the ideal gas law and the concept of absolute temperature. At standard temperature and pressure (STP), the temperature is 0°C or 273.15 K. A change of 1°C is equivalent to a change of 1 K, so the new temperature is 274.15 K. The fractional change in temperature is 1/273.15. Since pressure is directly proportional to temperature for a fixed volume and amount of gas (from the ideal gas law: P/T = constant), the fractional change in pressure is the same as the fractional change in temperature. The initial pressure at STP is 1 atm, which is equivalent to 101,325 Pa. Therefore, the change in pressure is 101,325 Pa * (1/273.15) ≈ 371 Pa.

A Vessel Contains 2