A force of 15.0 N is applied to a wire with an unstretched length of 4.00 m and a diameter of 5.00 mm. If the wire changed length by 1.20 mm, then the strain in the wire is A) 1.00 × 10⁻⁴. B) 2.00 × 10⁻⁴. C) 3.00 × 10⁻⁴. D) 4.00 × 10⁻⁴. E) 5.00 × 10⁻⁴.

Question

Quizplus · Accepted Answer

To find the strain in the wire, we use the formula:

strain = change in length / original length

The change in length is given as 1.20 mm, but we need to convert it to meters:

1.20 mm = 1.20 × 10^-3 m

The original length is given as 4.00 m.

So,

strain = (1.20 × 10^-3) / 4.00

strain = 3.00 × 10^-4

Therefore, the strain in the wire is 3.00 × 10^-4.

The answer is option C, 3.00 × 10^-4.

A Force of 15