A rod is 2.40 m long and has a diameter of 2.50 mm. A force of 2000 N is applied to the end, stretching the rod by 1.40 mm. What is the elastic modulus for this rod? A) 6.98 × 10¹¹ N/m² B) 1.75 × 10¹¹ N/m² C) 4.07 × 10⁸ N/m² D) 1.43 × 10⁶ N/m² E) 5.83 × 10⁻⁴ N/m²

Question

Quizplus · Accepted Answer

The elastic modulus (E) is calculated using the formula E = (F/A) / (ΔL/L), where F is the force applied, A is the cross-sectional area of the rod, ΔL is the change in length, and L is the original length. First, calculate the area A = πr^2 = π(1.25×10^-3)^2 m^2. Then, plug in the values: E = (2000 N / π(1.25×10^-3 m)^2) / (1.4×10^-3 m / 2.4 m) = 6.98×10^10 N/m^2.

A Rod Is 2