A viscous fluid is flowing through a small tube at a rate of 0.400 m3/s. If the pressure difference across the tube is tripled and the length of the tube is doubled, and the radius is also doubled, then what is the new rate of flow of the fluid? A) 9.6 m³/s B) 10.2 m³/s C) 12.00 m³/s D) 14.2 m³/s E) 15.5 m³/s

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Quizplus · Accepted Answer

According to Poiseuille's law, the flow rate Q is proportional to the pressure difference and the fourth power of the radius, and inversely proportional to the length. Tripling the pressure difference, doubling the radius, and doubling the length results in a new flow rate of 0.400 m³/s * (3 * (2^4) / 2) = 9.6 m³/s.

A Viscous Fluid Is Flowing Through a Small Tube at a Rate