A 6.00 kg mass is located at (2.00 m, 2.00 m, 2.00 m) and a 5.00 kg mass is located at (−1.0 m, 3.00 m, −2.00 m). The rotational inertia of this system of masses about the X-axis, perpendicular to the Z-Y plane, is A) 281 kg m². B) 167 kg m². C) 113 kg m². D) 85 kg m². E) 69 kg m².

Question

Quizplus · Accepted Answer

The rotational inertia (moment of inertia) about the X-axis is calculated using I = Σm(y² + z²). For the 6.00 kg mass, I₁ = 6.00 * (2.00² + 2.00²) = 48 kg m². For the 5.00 kg mass, I₂ = 5.00 * (3.00² + (-2.00)²) = 65 kg m². Total I = I₁ + I₂ = 113 kg m².

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